Cache shared across two decorated instances

Question

Accepted Answer

Both triple(4) and triple(7) are called twice, but the cache stores results by argument. The second triple(4) finds (4,) in the cache and returns without calling the original; same for the second triple(7). The original function body only runs for the first call with each unique argument, so hits increments to 1 for (4,) and then to 2 for (7,) - total 2. This reinforces the key behavior: the cache is keyed on arguments, and each unique argument set is computed exactly once.